Equations [Step3]


To solve an equation with brackets:
(A) First, remove the brackets.
To remove the brackets, multiply all the terms in the brackets with the term outside the brackets.
(B) Then, remove the x-terms from the right side, and remove the constant terms from the left side.
(C) Finally, divide each side by the coefficient of the left side x.
Example 1.
7x−3(x−2)=2x+10 …(A)
7x−3x+6=2x+10
Remove the brackets.
Multiply all the terms in the brackets with the term outside the brackets.
4x+6=2x+10 …(B)
4x−2x+6=2x−2x+10
2x+6=10
2x+6−6=10−6
Remove the x-terms from the right side, and remove the constant terms from the left side.
2x=4 …(C) In order to get x for itself, divide each side by the coefficient of the left side x.
x=2 (Solution)
Attention:
Example 2.
−2(4+x)=3(x−6) …(A) Remove the brackets.
Multiply all the terms in the brackets with the term outside the brackets.
−8−2x=3x−18 …(B) Move the x-terms to the left side, and move the constant terms to the right side.
−2x−3x=−18+8 Combine like terms..
−5x=−10 …(C) In order to get x for itself, divide each side by the coefficient of the left side x.
x=2 (Solution)
Attention:
ExercisesSolve these equations for x.
(Select the correct answers. // Result -> correct:o,incorrect:x)
(1) 3(x−2)=−5(x+6)
Remove the brackets from both sides.
(2) 3(3x−1)=−5(−2x−1)
Remove the brackets from both sides.
(3) −3(2−4x)=5(2x−3)
Remove the brackets from both sides.

(4) 2x−4(3−x)=6
Solution:
(5) 3x−7=2(x−4)
Solution:
(6) 2(x+1)−3(x−2)=7+2x
Solution:
Back to top menu
JPN MenuJPN Version