Solving Quadratic Equations by the Square Root Method

Square Root
If x2=a, then x=± (a≥0)
Example
1.x2=3x=±
2.x2=4x=±=±2
3.x2=12x=±=±2
Corollary 1
If ax2=b, then x=± (a>0, b≥0)
(Because)
ax2=bx2=x=±
Example
1.3x2=2x2=x=±
2.9x2=5x2=x=±
3.5x2=12x2=x=±

Corollary 2
If (x+a)2=b, then x=−a± (b≥0)
(Because)
(x+a)2=bx+a=±x=−a±
Example
1.(x+1)2=3x+1=±x=−1±
2.(x−2)2=9x−2=±=±3x=2±3=5, −1
3.2(x−3)2=5(x−3)2=x−3=±
x−3=±x=3±=
QuestionSolve the following equations by the Square Root Method.
(Choose a correct answer from the right column.)
[1 / 10]BackNext
Answer

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