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Introduction Roots (or radicals) are the inverse of exponents (or powers).
Examples
32=9 → =3 …(*) 53=125 → =5 24=16 → =2 (*) A radical without an index is understood to be a square root : = is called ”The Square Root”, is called ”The Cube Root”, … is called ”The n-th Root”. |
Symbols![]() |
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As is shown in the right figure, • if a>0 and n is an Even positive integer,
xn=a → 2 real x values satisfy the equation.
• if a>0 and n is an Odd positive integer,The positive value is denoted by . The negative value is denoted by −.
xn=a → Only 1 real x value satisfies the equation.
• if a>0 and n is an Even positive integer,The positive value is denoted by .
xn=−a → No real x value satisfies the equation.
• if a>0 and n is an Odd positive integer,
xn=−a → 1 real x value satisfies the equation.
• if a=0, either n is Even or Odd,The negative value is denoted by .
xn=0 → x=0
=0 (Always 1 value.)
In the following we will deal with positive radicands and those of positive n-th roots.
Therefore, either n is even or odd, there exists only one positive value denoted by for each a, n. (See the blue curve of the right Figure.) |
Even index and Odd index![]() |
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Basic Rule to simplify the n-th radicals. To simplify a radical means to remove nth powers from the radicand (the number inside the radical). You can simplify a radical if the radicand has the powers greater than or equal to the index n.
=a
By definitionIf b is not expressed by the n-th power of any integer, =a xn=a → x= So When x=a (a>0) xn=an → x= ∴=a |
Examples (1)==2 (2)==2 (A radical without an index is understood to be a square root.) (3)===2 (4)==5 (5)==2 (6)==2 |
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QuestionSimplify the radicals. |
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Laws of Radicals
Suppose a>0, b>0 and m, n, p are positive integers.
(1)= …(1) (2)= …(2) (3)( )m= …(3) (4)= …(4) (5)= …(5)
Sorry to say, these rules are used only as a guide.
(Proof)You had better calculate by the equivalent Fractional Exponents rather than by these Laws of Radicals directly. (1)←
Let x=
Similarly, (2) can be shown.Then xn=()n=ab According to the definition : xn=a → x= x= Therefore = (3)←
Let x=()m
Then xn=()mn=(()n)m=am According to the definition : xn=a → x= x= Therefore ( )m= |
Examples (1)= (2)= (3)( )4= (4)= (5)= (4)←
Let x=
(5)←Then xmn=()mn=(()m)n As ()m= xmn=()n=a Let y= Then ymn=()mn=a Therefore x=y (x, y>0) =
Let x=
Then xnp=()np=amp Let y= Then ynp=()np=(()n)p=(am)p=amp Therefore x=y (x, y>0) = |